WebSolution: The sum of n terms S n = 441 Similarly, S n-1 = 356 a = 13 d= n For an AP, S n = (n/2) [2a+ (n-1)d] Putting n = n-1 in above equation, l is the last term. It is also denoted by a n. The result obtained is: S n -S n-1 = a n So, 441-356 = a n a n = 85 = 13+ (n-1)d Since d=n, n (n-1) = 72 ⇒n 2 – n – 72= 0 Solving by factorization method, WebFirst of all, the arbitrary term should be 1/n·(n+4), not 1/n·(n+1). But okay, let's try to find the sum from n=1 to ∞ of 1/n·(n+4). We'll start by rewriting this with partial fractions. So we …
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WebEnglish Medium Class 10 In an AP, if Sn = n (4n + 1), find the AP. - Mathematics Advertisement Remove all ads Advertisement Remove all ads Sum In an AP, if S n = n (4n … WebMar 16, 2024 · Answer: d = -2 Step-by-step explanation: Because the sum of first n terms of any AP is in the form (d/2)n² + (a - d/2)n, where d is the common difference and a is the …
WebIn an AP, if Sn = n (4n+1), then find the AP. Solution We know that, the nth term of an AP is; an= Sn−Sn−1 an= n(4n+1)−(n−1){4(n−1)+1} [∵ Sn= n(4n+1)] ⇒ an =4n2+n−(n−1)(4n−3) ⇒ … WebIn an AP, if Sₙ = n (4n + 1), find the AP Solution: Given, the expression for the sum of the terms is Sₙ = n (4n + 1) We have to find the AP. Put n = 1, S₁ = 1 (4 (1) + 1) = 4 + 1 = 5 Put n …
WebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, WebCorrect option is A) Given, S n=4n 2−n When n=1 , S 1=4(1) 2−1=4−1=3 Now, obviously, the sum of the first term will be the first term itself, as there are no other terms involved. When n=2 , S 2=4(2) 2−1=16=2=14 The sum of the first 2 terms is equal to a 1+a 2 Therefore, a 1+a 2=14 We have shown, above, that a 1=3 Substituting it in a 1+a 2=14,
WebMar 31, 2024 · If the sum of n terms of an A.P. is 2n^2 + 5n , then its nth term is A. 4n − 3 B. 3n − 4 C. 4n + 3 D. 3n + 4 asked Jul 16, 2024 in Arithmetic Progression by Maanas ( 26.0k points) arithmetic progression
WebIn an AP, if d = – 4, n = 7 and a n = 4, then a is equal to (a) 6 (b) 7 (c) 20 (d) 28 Solution: Question 2: In an AP, if a = 3.5, d = 0 and n = 101, then a n will be (a) 0 (b) 3.5 (c) 103.5 (d) 104.5 Solution: (b) For an AP a n = a + (n – 1)d= 3.5+ (101 – 1 )x 0 [by given conditions] ∴ = 3.5 Question 3: The list of numbers – 10, – 6, – 2, 2,… is destiny 2 pale heartWebMar 16, 2024 · Answer: d = -2 Step-by-step explanation: Because the sum of first n terms of any AP is in the form (d/2)n² + (a - d/2)n, where d is the common difference and a is the first term. So that the coefficient of n² is half of the common difference. Here in S_n = 4n - n², the coefficient of n² is -1, so that half of common difference is -1. destiny 2 out of bounds pvp god rollWebNCERT Exemplar Class 10 Maths Exercise 5.3 Sample Problem 1. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, find the value of n. Summary: An arithmetic progression is a sequence where each term, except the first term, is obtained by adding a fixed number to its previous term. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, then the value ... chudleigh devon hoseasonsWebFind the A.P. whose sum to n terms is 2n 2 +n A The required A.P. is 2,6,10,14,... B The required A.P. is 3,7,11,15,... C The required A.P. is 4,8,12,16,... D The required A.P. is 5,10,15,20,... Medium Solution Verified by Toppr Correct option is B) Given, S n=2n 2+n Now, a 1=S 1=2(1) 2+1=3 a 2=S 2−S 1=2(2) 2+2−3=7 destiny 2 ouroboreaWebJan 11, 2016 · IN an AP, if sn=n[4n+1] find the AP. Asked by archita123 11 Jan, 2016, 06:12: PM Expert Answer Answered by 11 Jan, 2016, 06:22: PM Application Videos. This … destiny 2 osteo striga hunter buildWebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin … destiny 2 osiris boostWebMar 29, 2024 · Given Sn = 4n – n2 Taking n = 1 S1 = 4 × 1−12 = 4 – 1 = 3 ∴ Sum of first term of AP is 3 Taking n = 2 in Sn S2 = 4×2−2^2 S2 = 8 – 4 S2 = 4 ∴ Sum of first 2 terms is 4 But … destiny 2 overload intrinsic